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A charge of #5 C# passes through a circuit every #2 s#. If the circuit can generate #25 W# of power, what is the circuit's resistance?

Answer 1

Benjamin Asiedu

The resistance of the circuit is 25 ohms.

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Answer 2

Isabella Alvarez

#=4Omega#

We know #"Current"(I)=("Charge passed"(q))/("Time"(t))=5/2A=2.5A# Again #Power(P)=I^2xxR# Therefore Resistance #R =P/I^2=25/2.5^2=4Omega#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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