A charge of #35 C# passes through a circuit every #5 s#. If the circuit can generate #84 W# of power, what is the circuit's resistance?

Answer 1

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Answer 2

To find the resistance of the circuit, we can use the formula for power in terms of current and resistance:

Power (P) = Current (I) * Voltage (V)

We can rearrange this formula to solve for resistance:

Resistance (R) = Voltage (V) / Current (I)

We are given the power (P) as 84 W, and we know that power is equal to voltage multiplied by current. We are also given the current (I) as the charge passing through the circuit every 5 seconds. The charge is given as 35 C and the time interval is 5 s. So, we can calculate the current (I) as:

Current (I) = Charge (Q) / Time (t) = 35 C / 5 s = 7 A

Now, we can use the formula for power to find the voltage (V):

Power (P) = Voltage (V) * Current (I)

84 W = Voltage (V) * 7 A

Voltage (V) = 84 W / 7 A = 12 V

Finally, we can use the formula for resistance to find the resistance (R):

Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 12 V / 7 A ≈ 1.71 Ω

Therefore, the circuit's resistance is approximately 1.71 ohms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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