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A charge of #30 C# passes through a circuit every #5 s#. If the circuit can generate #42 W# of power, what is the circuit's resistance?

Answer 1

Olivia Askew

#R= 7/6Omega#

Current is charge divided by time:

#I = (30"C")/(5"s") = 6"A" #

Power it the square of the current multiplied by the resistance:

#P = I^2R#

#42"W" = (6"A")^2R#

#R= 42/36Omega#

#R= 7/6Omega#

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Answer 2

Axel Acevedo

The resistance of the circuit is 70 ohms. Use the formula: Power (W) = Current (I) * Voltage (V), and Ohm's Law: Voltage (V) = Current (I) * Resistance (R).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.