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A charge of #27 C# passes through a circuit every #3 s#. If the circuit can generate #72 W# of power, what is the circuit's resistance?

Answer 1

Emily Abbate

#R=8/9 Ohm#

#"given data:"# #q=27C" charge"# #Delta t=3 s" time interval"# #P=72W" Power"# #R=?" Resistance"#

#so" " P=I^2*R#

#"we must calculate the electric current I"# #I=(Delta q)/(Delta t)#

#I=27/3=9A#

#cancel(72)=cancel(9)^2*R#

#8=9*R#

#R=8/9 Ohm#

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Answer 2

William Audy

Use the formula P = VI. Rearrange it to solve for resistance (R), where R = P/I².

Calculate voltage (V) using V = Q/t.

Substitute values into the formula: R = (V²/P) = [(Q/t)² / P].

Insert the given values: R = [(27 C / 3 s)² / 72 W].

Calculate the resistance: R = 9 Ω.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.