A charge of #25 C# passes through a circuit every #4 s#. If the circuit can generate #1 W# of power, what is the circuit's resistance?

Answer 1

To find the resistance of the circuit, you can use the formula:

P = V * I

Where: P is the power (1 W), V is the voltage, and I is the current.

Given that the charge passing through the circuit every 4 seconds is 25 C, you can calculate the current using:

I = Q / t

Where: Q is the charge (25 C), t is the time (4 s).

Once you have the current, you can rearrange the power formula to solve for resistance:

R = V / I

Substitute the given values to find the resistance of the circuit.

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Answer 2

The circuit resistance is #=25.6mOmega#

We apply the equation

#Q=It#
The charge is #Q=25C#
The time is #t=4s#
The current is #I=Q/t=25/4A#

The power

#P=UI#

But according to Ohm's Law

#U=RI#

So,

#P=RI*I=RI^2#

So,

the resistance is #R=P/I^2#
#=1/(25/4)^2=0.0256Omega#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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