A charge of #24 C# passes through a circuit every #9 s#. If the circuit can generate #16 W# of power, what is the circuit's resistance?

Answer 1

To find the circuit's resistance, we can use the formula for power in an electrical circuit:

Power (P) = (Voltage)^2 / Resistance

Given that the circuit generates 16 W of power and knowing the charge passing through the circuit every 9 s, we can calculate the voltage using the formula:

Voltage (V) = Charge / Time

Then, rearranging the power formula to solve for resistance:

Resistance (R) = Voltage^2 / Power

Substitute the values into the equation and solve for resistance:

Resistance (R) = (Voltage)^2 / Power

Resistance (R) = ( (Charge / Time) )^2 / Power

Resistance (R) = ( (24 C / 9 s) )^2 / 16 W

Resistance (R) = (2.67 V)^2 / 16 W

Resistance (R) ≈ 0.445 ohms

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Answer 2

Nathan Ashcroft

#R=2,25 " "Ohm#

#"the electric current is given as:"# #I=(Delta Q)/(Delta t)#

#Delta Q=24 C" "Delta t=9 " s"#

#I=24/9=8/3 " "A#

#"P=Power R:Resistance"#

#P=I^2*R# #16=(8/3)^2*R#

#cancel(16)=cancel(64)/9*R#

#R=9/4#

#R=2,25 " "Ohm#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.