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A charge of #24 C# passes through a circuit every #6 s#. If the circuit can generate #12 W# of power, what is the circuit's resistance?

Answer 1
William AudyWilliam Audy

Resistance = 2 ohms.

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Answer 2
Adrian AyalaAdrian Ayala

#0.75Omega#

Calculate current, #I#, by
#I = Q/t = (24C)/(6s) = 4A#

Electrical power is given by

#P = IV = I^2R#

so

#R = P/I^2 = (12W)/(4A)^2 = 0.75Omega#
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Answer 3
Olivia AskewOlivia Askew

#0.75Omega#

Calculate current, #I#, by
#I = Q/t = (24C)/(6s) = 4A#

Electrical power is given by

#P = IV = I^2R#

so

#R = P/I^2 = (12W)/(4A)^2 = 0.75Omega#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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