A charge of #24 C# passes through a circuit every #18 s#. If the circuit can generate #16 W# of power, what is the circuit's resistance?

Answer 1

The resistance of the circuit can be calculated using the formula:

Resistance (R) = Voltage (V) / Current (I)

Given that Power (P) = Voltage (V) × Current (I), and Power (P) = 16 W, and Charge (Q) = 24 C, and Time (t) = 18 s, we can find the current using:

Current (I) = Charge (Q) / Time (t)

Then, using the formula for power, we can find the voltage:

Voltage (V) = Power (P) / Current (I)

Finally, using the formula for resistance, we can find the resistance:

Resistance (R) = Voltage (V) / Current (I)

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Answer 2

#9Omega#

You can work out the current by charge and time,

#I = Q/t = 24/18 = 1.33A#

which you can then use to work out power, by

#P = IV = I(IR) = I^2R#

Since we know current and power, and we want the resistance, then

#R = P/I^2 = 16/1.33^2 = 9Omega#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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