A charge of #-2 C# is at #(6 , -5 )# and a charge of #-4 C# is at #(-3 , -9 ) #. If both coordinates are in meters, what is the force between the charges?
The force between the charges is
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Use Coulomb's Law: ( F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} ) where ( k ) is Coulomb's constant (8.99 × 10^9 N m²/C²), ( q_1 ) and ( q_2 ) are the charges, and ( r ) is the distance between them.
[ F = \frac{(8.99 \times 10^9) \cdot |-2 \cdot (-4)|}{(6 - (-3))^2 + ((-5) - (-9))^2} ]
Calculate to find the force.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- What is the force, in terms of Coulomb's constant, between two electrical charges of #7 C# and #-9 C# that are #9 m # apart?
- A 3.26-kg toy car starts at a point B and then is raised to a second point A that is 5.0 metres higher. By what amount has the potential energy of the car changed as a result?
- An electric toy car with a mass of #15 kg# is powered by a motor with a voltage of #8 V# and a current supply of #7 A#. How long will it take for the toy car to accelerate from rest to #9 m/s#?

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