A charge of #18 C# passes through a circuit every #4 s#. If the circuit can generate #24 W# of power, what is the circuit's resistance?

Answer 1

To find the circuit's resistance, we can use the formula for power:

Power (P) = Current (I) × Voltage (V)

We can find the current using the formula:

Current (I) = Charge (Q) / Time (t)

Substitute the given values:

Current (I) = 18 C / 4 s = 4.5 A

Now, we can rearrange the power formula to solve for resistance:

Resistance (R) = Voltage (V) / Current (I)

We know the power (P) is 24 W. We can rearrange the power formula to solve for voltage:

Voltage (V) = Power (P) / Current (I)

Substitute the known values:

Voltage (V) = 24 W / 4.5 A ≈ 5.33 V

Now, we can find the resistance:

Resistance (R) = 5.33 V / 4.5 A ≈ 1.18 Ω

So, the circuit's resistance is approximately 1.18 ohms.

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Answer 2

#R~=1,185" Ohm"#

#"calculate current using the formula :"I=(Delta Q)/(Delta t)# #I=18/4=9/2A# #"use the power formula :"P=I^2*R# #24=(9/2)^2*R# #24=81/4*R# #R=(24*4)/81# #R~=1,185" Ohm"#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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