Home > Physics > Electric Potential

A charge of #16 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #38 J# to #12 J#, what is the voltage between points A and B?

Answer 1

Parker Abbott

The voltage between points A and B can be calculated using the formula:

V = ΔPE / q

Where: V is the voltage, ΔPE is the change in electric potential energy, and q is the charge.

Given: ΔPE = 38 J - 12 J = 26 J (change in electric potential energy) q = 16 C (charge)

Substituting the values into the formula:

V = 26 J / 16 C

V = 1.625 volts

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Nathan Ashcroft

#V_(AB)=-1,625 " V"#

#Delta W=q*(V_B-V_A)# #12-38=16*V_(AB)# #-26=16*V_(AB)# #V_(AB)=(-26)/16# #V_(AB)=-1,625 " V"#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.