A charge of #16 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #27 J# to #3 J#, what is the voltage between points A and B?

Answer 1

A and B differ by 1.5 volts.

The relation you need is essentially the definition of voltage (electric potential):

W = qV

where W is the change in electric potential energy, q is the quantity of charge transported and V is the potential difference (or voltage difference) between the two points.

(Incidentally, your question should read: A charge of 16 C is passing through points A and B on a circuit. If the charge's electric potential energy changes from 27 J to 3 J, what is the voltage between points A and B?)

Anyway, here we go:

24 J = 16 C x V

V = #24/16# #J/C#= 1.5 volts

(Note: The unit volt is identical to the combined units joules per coulomb)

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Answer 2

Nicholas Agrusa

The voltage between points A and B is 1.5 V.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.