A charge of #12 C# passes through a circuit every #6 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

Answer 1

The circuit's resistance can be calculated using the formula:

Resistance (R) = Voltage (V) / Current (I)

Given that Power (P) = Voltage (V) * Current (I), and Power (P) = 8 W, and Charge (Q) = 12 C passes through the circuit every 6 s, we can calculate the current (I) using the formula:

Current (I) = Charge (Q) / Time (t)

Then, we can find the resistance (R) using the formula:

Resistance (R) = Voltage (V) / Current (I)

Substitute the values and solve for resistance (R).

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Answer 2

Emily Abbate

The resistance is 2 ohm

I= #q/t# here I = current strength,q = charge passing in t sec = 12C and t =6 sec. So i = 2amp power (P) = #I^2R#, where R = Resistance P= 8W Hence R= #8/(2*2)# =2ohm

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.