# A charge of #12 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #60 J# to #34 J#, what is the voltage between points A and B?

To find the voltage between points A and B, we use the formula:

[V = \frac{ΔE}{q}]

Where:

- (V) is the voltage,
- (ΔE) is the change in electric potential energy (final electric potential energy - initial electric potential energy), and
- (q) is the charge.

Given:

- (ΔE = 34 J - 60 J = -26 J)
- (q = 12 C)

Plugging in the values:

[V = \frac{-26 J}{12 C} = -\frac{13}{6} V]

So, the voltage between points A and B is (-\frac{13}{6} V).

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The voltage is

The Energy is

The change in energy is

Therefore,

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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