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A charge of #1 C# is at #(-7, 1 )# and a charge of #-3 C# is at #(3, 5 ) #. If both coordinates are in meters, what is the force between the charges?

Answer 1

Charles Aeschliman

#2.33xx10^5#

We must first measure the distance.

#r=sqrt((3+7)^2+(5-1)^2)# #=sqrt(100+16)# #=sqrt116#

As we are aware,

#F=1/(4piepsilon)(q_1q_2)/r^2#

#=9xx10^9xx(1xx-3)/116#

#=2.33xx10^5#

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Answer 2

Lily Adams

Use Coulomb's Law to find the force between the charges:

[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} ]

where ( F ) is the force, ( k ) is Coulomb's constant ((8.99 \times 10^9 \ \text{N m}^2/\text{C}^2)), ( q_1 ) and ( q_2 ) are the charges, ( r ) is the distance between the charges.

Calculate ( r ) using the distance formula: [ r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ]

Substitute the values and solve for ( F ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.