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A change purse contains an equal number of pennies, nickels, and dimes. The total value of the coins is #$2.40#. How many coins of each does the purse have?

Answer 1

Everly Taylor

There are #15# coins of each denomination.

Each penny is one cent, each nickel is #5# cents and each dime is #10# cents

Let there be #k# number of each and therefore their value is

#10k+5k+k=240#

#16k=240#

#k=240/16=15#

Hence, there are #15# coins of each denomination.

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Answer 2

Benjamin Altschul

Let (x) represent the number of each type of coin (pennies, nickels, and dimes).

The value of the pennies is (0.01x), the value of the nickels is (0.05x), and the value of the dimes is (0.10x).

The total value of the coins is given as $2.40, so we can set up the equation:

(0.01x + 0.05x + 0.10x = 2.40)

Solving for (x):

(0.01x + 0.05x + 0.10x = 2.40) (0.16x = 2.40) (x = \frac{2.40}{0.16}) (x = 15)

So, there are 15 of each type of coin in the change purse: 15 pennies, 15 nickels, and 15 dimes.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.