# A change purse contains an equal number of pennies, nickels, and dimes. The total value of the coins is #$2.40#. How many coins of each does the purse have?

There are

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Let (x) represent the number of each type of coin (pennies, nickels, and dimes).

The value of the pennies is (0.01x), the value of the nickels is (0.05x), and the value of the dimes is (0.10x).

The total value of the coins is given as $2.40, so we can set up the equation:

(0.01x + 0.05x + 0.10x = 2.40)

Solving for (x):

(0.01x + 0.05x + 0.10x = 2.40) (0.16x = 2.40) (x = \frac{2.40}{0.16}) (x = 15)

So, there are 15 of each type of coin in the change purse: 15 pennies, 15 nickels, and 15 dimes.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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