A card is drawn from a well-shuffled deck of 52 cards. How do you find P(drawing an ace or a 9)?
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To find the probability of drawing an ace or a 9 from a well-shuffled deck of 52 cards, you add the probabilities of drawing each separately and then subtract the probability of drawing both an ace and a 9, since drawing both simultaneously is not possible:
P(drawing an ace or a 9) = P(ace) + P(9) - P(ace and 9)
There are 4 aces and 4 9s in a standard deck of cards:
P(ace) = 4/52 P(9) = 4/52
There are 4 cards that are both an ace and a 9 (the ace of hearts, diamonds, clubs, and spades):
P(ace and 9) = 4/52
Substituting the values:
P(drawing an ace or a 9) = (4/52) + (4/52) - (4/52)
P(drawing an ace or a 9) = 8/52
Simplify the fraction:
P(drawing an ace or a 9) = 2/13
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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