# A car repair shop charged $80 per hour for labor and $210 for the parts of a car. If the total cost was $490, how many hours did it take to repair the car?

Subtract the cost of parts from total cost. This will leave us with the cost of labour.

Dividing cost of labour by $80 will give the number of hours spent on repairing the car.

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Here total cost is $490 and cost of the parts is$210. So, total repair charge = $490-$210 = $280.

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Let ( x ) represent the number of hours it took to repair the car.

The total cost of labor is given by ( 80x ) dollars.

Given that the total cost of parts is $210, and the total cost is$490, the total cost of labor and parts is ( 80x + 210 ).

Setting up the equation:

[ 80x + 210 = 490 ]

Subtracting 210 from both sides:

[ 80x = 280 ]

Dividing both sides by 80:

[ x = \frac{280}{80} ]

[ x = 3.5 ]

Therefore, it took 3.5 hours to repair the car.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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