# A car driving at 41m/s hits the brakes and comes to a stop in 4.8 seconds. What was the car's acceleration during this stop?

QuestionAnswer 1

If #u# = initial velocity

#v# = final velocity

#t# = time:

#a# = accelaration

#a=(u-v)/(t)#

#a =(0-41)/(4.8)=-8.54" "m.s^-2 #

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Answer 2

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