A car driving at 41m/s hits the brakes and comes to a stop in 4.8 seconds. What was the car's acceleration during this stop?

Answer 1

Benjamin Asiedu

#a=-8.54" "m.s^-2#

The rate at which velocity changes is called acceleration.

If #u# = initial velocity

#v# = final velocity

#t# = time:

#a# = accelaration

#a=(u-v)/(t)#

#a =(0-41)/(4.8)=-8.54" "m.s^-2 #

The car is slowing down, as indicated by the minus sign.

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Answer 2

Lily Adams

The car's acceleration during the stop was approximately -8.54 m/s².

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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