A bullet traveling at 250 meters per second is brought to rest by an impulse of 5.00 newton-seconds. What is the mass of the buIIet?

We know that Impulse is equal to Change in momentum Mathematically stated this equation is known as the impulse-momentum change equation.

To find the mass of the bullet, you can use the impulse-momentum theorem, which states that impulse is equal to the change in momentum.

Impulse (J) = Change in momentum (Δp)

Impulse (J) = Force (F) * Time (Δt)

Given that impulse (J) = 5.00 N·s and initial velocity (v_i) = 250 m/s (since the bullet is brought to rest, the final velocity (v_f) is 0), you can calculate the change in momentum (Δp).

Δp = m * Δv

Where m is the mass of the bullet and Δv is the change in velocity.

Δv = v_f - v_i = 0 - 250 = -250 m/s

Now, using the formula for impulse:

J = F * Δt

Rearranging for force:

F = J / Δt

Given that J = 5.00 N·s, and using the formula for force:

5.00 N·s = F * Δt

Now, we know that Δt = time = m / F

Substituting the known values:

5.00 N·s = F * (m / F)

Solving for m:

m = J / Δv

m = 5.00 N·s / -250 m/s

m ≈ -0.02 kg

However, mass cannot be negative, so there may be an error in the calculation or the given information. Double-check the problem to ensure accuracy.