A box with a mass of 14.8 kg sits on the floor. How high would you have to lift box to for it to have a gravitational potential energy of 355 J?

Answer 1

#2.45m#

#E = mgh#
where #E# is the gravitational potential energy, #m# is the mass of the box, #g# is the gravitational field strength (#9.81# on earth) and #h# is the height.

The question asks us about height, so

#h = E/(mg) = 355/(14.8 xx 9.81) = 2.45m#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To calculate the height you would need to lift the box for it to have a gravitational potential energy of 355 J, you can use the formula for gravitational potential energy:

Gravitational Potential Energy = Mass × Gravity × Height

Given that the mass of the box is 14.8 kg and the gravitational potential energy is 355 J, and assuming the acceleration due to gravity is approximately (9.8 , \text{m/s}^2), we can rearrange the formula to solve for height:

Height = Gravitational Potential Energy / (Mass × Gravity)

Height = 355 J / (14.8 kg × 9.8 m/s²)

Height ≈ 2.42 meters

Therefore, you would need to lift the box to a height of approximately 2.42 meters for it to have a gravitational potential energy of 355 J.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7