A bottle of juice has a deposit of $.10 on the bottle. How much deposit money would there be on 8 bottles?

Answer 1

#=0.8$#

#0.1times8#
#=0.8$#
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Answer 2

#color(green)("A sort of cheat method ")#

The amount of deposit on 8 bottles is $0.80

The traditional way would to write:

#0.10# #ul(color(white)(0.1)8)" "larr" multiply"#
Then we multiply and follow a rule that gives us the position of the decimal point. '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #color(brown)("Let try and ignore the decimal point for now by writing")# #color(brown)(0.1" as "10-:100 -> 10xx1/100)#
So we now have #8xx10xx1/100#
Consider just the #8xx10#
#8xx10=80# '~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Now we bring in the #xx1/100# giving
#80xx1/100 = 0.8#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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