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A beaker contains 0.32 L of water. What is the volume of this in milliliters?

Answer 1
Owen AmbroseOwen Ambrose

#320*mL#

The #"milli"# prefix #-=# #10^-3#. And thus #1*mL# #-=# #10^-3*L#.
And so #0.32*L-=0.32*cancel(L)xx10^3*mL*cancel(L^-1)=320*mL.#
Sometimes (especially in Old Blighty), we use the #"cubic decimeter"# to represent #1*L#. How? Well there are #1000*L# in a #"cubic meter"#, a rather large volume, that is certainly no good as a unit of measurement in a lab.........
But #1*dm^3=(1xx10^-1*m)^3=10^-3*m^3=1*L# as required.........
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Answer 2
Olivia AntonOlivia Anton

The volume of 0.32 L of water is 320 milliliters.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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