A balloon with a volume of 5.3 L is taken from an indoor temperature of 24 C to the outdoors. The volume of the balloon outside is 4.9 L. How do you determine the C temperature outside?

Answer 1

The outside temperature is 0 °C.

Given

The volume #V_1# of a gas at a temperature #T_1#. A second volume #V_2#

Find

The second temperature #T_2#

Strategy

A problem involving two gas volumes and two temperatures must be a Charles' Law problem.

The formula for Charles' Law is

#color(blue)(|bar(ul(color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)|)))" "#

Solution

We can rearrange Charles' Law to get

#T_2 = T_1 × V_2/V_1#

In your problem,

#V_1 = "5.3 L"#; #T_1 = (24 + 273.15) K = "297.15 K"# #V_2 = "4.9 L"#; #T_2 = "?"#
∴ #T_2 = "297.15 K" × (4.9 cancel("L"))/(5.3 cancel("L")) = "274 K"#
#"200 K" = "(274 - 273.15) °C" = "0 °C"#

The outside temperature is 0 °C.

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Answer 2

To determine the temperature outside, you can use the combined gas law, which states: (P1 * V1) / T1 = (P2 * V2) / T2. Rearrange the equation to solve for T2: T2 = (P2 * V2 * T1) / (P1 * V1). Substitute the given values: P1 (indoors) is atmospheric pressure at 24°C, V1 is the initial volume (5.3 L), P2 (outdoors) is atmospheric pressure, V2 is the final volume (4.9 L), and T1 is the initial temperature (24°C). Calculate T2 using the equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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