A balloon has a volume of 20.0 L at atmospheric pressure and 20.0 C. One wants to increase the volume to 24.0 L at constant pressure. To what temperature in degrees Celsius does one need to increase the temperature to?

Answer 1

The answer is 79 °C.

As the initial volume of 20 L is less than the final volume of 24 L, the temperature must increase.

This is based on Charles' Law, which states that there is a direct relationship between temperature and volume.

If your answer is less than 20 L, the answer is wrong.

It is important to remember that Charles' Law is based on Kelvin temperatures.

Step one is to change Celsius degrees into kelvins.

#"0 °C" = "273 K"#
∴ #T_1 = "(20 + 273) K" = "293 K"#

Step two is to insert the values into the Charles' Law expression.

# T_1/V_1 = T_2/V_2#
#"293 K"/"20 L" = T_2/"24 L"#
# 24 × "293 K"/20 = T_2#
#"352 K" = T_2#

Step three is to convert the Kelvin temperature to Celsius.

To change this answer back to Celsius degrees, subtract 273.

#"(352-273) °C"color(white)(l) =color(white)(l) "79 °C"#
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Answer 2

To increase the volume of the balloon from 20.0 L to 24.0 L at constant pressure, the temperature needs to be increased to 240 K.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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