A ball with a mass of #1 kg# moving at #1 m/s# hits a still ball with a mass of #8 kg#. If the first ball stops moving, how fast is the second ball moving?

Answer 1

The velocity of the second ball after the collision is #=0.125ms^-1#

We have conservation of momentum

#m_1u_1+m_2u_2=m_1v_1+m_2v_2#
The mass the first ball is #m_1=1kg#
The velocity of the first ball before the collision is #u_1=1ms^-1#
The mass of the second ball is #m_2=8kg#
The velocity of the second ball before the collision is #u_2=0ms^-1#
The velocity of the first ball after the collision is #v_1=0ms^-1#

Therefore,

#1*1+8*0=1*0+8*v_2#
#8v_2=1#
#v_2=1/8=0.125ms^-1#
The velocity of the second ball after the collision is #v_2=0.125ms^-1#
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Answer 2

The second ball will move at a speed of 0.125 m/s in the opposite direction.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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