A ball with a mass of #1 kg # and velocity of #5 m/s# collides with a second ball with a mass of #3 kg# and velocity of #- 2 m/s#. If #20%# of the kinetic energy is lost, what are the final velocities of the balls?

Answer 1

-0.20 m/s (Ball A reverses direction)

First we calculate the total momentum energy available. Then we calculate the result with no energy loss, and finally we apply the 20% energy reduction to both results.

Ball A: 1kg * 5m/s = 5 kg-m/s Ball B: 3kg * -2m/s = -6 kg-m/s

Resultant: Both balls have momentum of -1 kg-m/s with a combined mass of 4 kg. Therefore the velocity is -0.25 m/s. If 20% of the energy is lost, this is reduced to -0.20 m/s.

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Answer 2

Leo Abeyta

The final velocity of the 1 kg ball is approximately 1.8 m/s, and the final velocity of the 3 kg ball is approximately -0.6 m/s.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.