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A balanced lever has two weights on it, the first with mass #9 kg # and the second with mass #32 kg#. If the first weight is # 4 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Amelia Adams

The distance is #=1.125m#

The mass #M_2=9kg#

The mass #M_1=32kg#

The distance #b=4m#

Taking the moments about the fulcrum

#M_1*g*a=M_2*g*b#

#32*g*a=9*g*4#

#a=36/32=1.125m#

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Answer 2

Parker Abbott

To find the distance of the second weight from the fulcrum, use the formula: ( \text{weight}_1 \times \text{distance}_1 = \text{weight}_2 \times \text{distance}_2 ). Therefore, ( 9 , \text{kg} \times 4 , \text{m} = 32 , \text{kg} \times \text{distance}_2 ). Solving for distance_2, the second weight is approximately 1.125 m from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.