A balanced lever has two weights on it, the first with mass #9 kg # and the second with mass #72 kg#. If the first weight is # 16 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Layla Ahmed

#y=2m#

#F_1*x=F_2*y# #cancel(9)*16=cancel(72)*y# #cancel(16)=cancel(8)*y# #y=2m#

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Answer 2

Olivia Askew

To find the distance of the second weight from the fulcrum, we can use the principle of moments, which states that the sum of the moments acting on a balanced lever is zero. The moment (or torque) of a force about a point is calculated by multiplying the force by the distance from the point. Therefore, we can set up the equation:

(9 \times 16 = 72 \times d)

Solving for (d), we get:

(d = \frac{9 \times 16}{72} = \frac{144}{72} = 2) meters.

So, the second weight is 2 meters from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.