A balanced lever has two weights on it, the first with mass #9 kg # and the second with mass #4 kg#. If the first weight is # 12 m# from the fulcrum, how far is the second weight from the fulcrum?
The distance is
The acceleration due to gravity is The mass The mass The distance Taking moments about the fulcrum So,
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To find the distance of the second weight from the fulcrum, use the formula: ( \text{Weight}_1 \times \text{Distance}_1 = \text{Weight}_2 \times \text{Distance}_2 ). Therefore, ( 9 , \text{kg} \times 12 , \text{m} = 4 , \text{kg} \times \text{Distance}_2 ). Solve for Distance_2. The second weight is 27 m from the fulcrum.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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