# A balanced lever has two weights on it, the first with mass #72 kg # and the second with mass #9 kg#. If the first weight is # 4 m# from the fulcrum, how far is the second weight from the fulcrum?

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To find the distance of the second weight from the fulcrum, you can use the principle of moments:

( \text{Moment}_1 = \text{Moment}_2 )

Where ( \text{Moment}_1 = \text{force}_1 \times \text{distance}_1 ) and ( \text{Moment}_2 = \text{force}_2 \times \text{distance}_2 ).

Given: ( \text{force}_1 = 72 \text{ kg} ), ( \text{distance}_1 = 4 \text{ m} ), ( \text{force}_2 = 9 \text{ kg} ), ( \text{distance}_2 = ? )

Rearrange the equation to solve for ( \text{distance}_2 ): ( \text{distance}_2 = \frac{\text{Moment}_1}{\text{force}_2} - \text{distance}_1 )

Substitute the given values: ( \text{distance}_2 = \frac{(72 \text{ kg} \times 4 \text{ m})}{9 \text{ kg}} - 4 \text{ m} )

( \text{distance}_2 = 32 \text{ m} - 4 \text{ m} )

( \text{distance}_2 = 28 \text{ m} )

Therefore, the second weight is 28 meters from the fulcrum.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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