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A balanced lever has two weights on it, the first with mass #7 kg # and the second with mass #4 kg#. If the first weight is # 6 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Charlotte Aaron

The distance is #=10.5m#

The mass #M_1=7kg#

The mass #M_2=4kg#

The distance #a=6m#

Taking moments about the fulcrum

#M_1xxa=M_2xxb#

#b=(M_1xxa)/(M_2)=(7xx6)/(4)=10.5m#

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Answer 2

Layla Ahmed

To find the distance of the second weight from the fulcrum, we can use the principle of moments, which states that the total clockwise moment equals the total anticlockwise moment in a balanced lever.

The moment of a force (torque) is given by:

moment = force * distance

Given: Mass of the first weight (m1) = 7 kg Mass of the second weight (m2) = 4 kg Distance of the first weight from the fulcrum (d1) = 6 m Distance of the second weight from the fulcrum (d2) = ?

Since the lever is balanced:

Moment of first weight = Moment of second weight

(m1 * d1) = (m2 * d2)

Substituting the given values:

(7 kg * 6 m) = (4 kg * d2)

Solve for d2:

42 m = 4 kg * d2

d2 = 42 m / 4 kg

d2 = 10.5 m

So, the distance of the second weight from the fulcrum is 10.5 meters.

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Answer from HIX Tutor

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