A balanced lever has two weights on it, the first with mass #7 kg # and the second with mass #3 kg#. If the first weight is # 2 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

#4.667# meters

In a balanced lever, product of mass of one weight and its distance from fulcrum is equal to the mass of other weight and its distance from the fulcrum. As the product is #14# in first weight, the distance of second weight from fulcrum would be #14/3# i.e. #4.667# meters.

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Answer 2

Leo Abeyta

To find the distance of the second weight from the fulcrum, use the formula for a balanced lever:

( \text{Mass}_1 \times \text{Distance}_1 = \text{Mass}_2 \times \text{Distance}_2 )

Substitute the given values:

( 7 \times 2 = 3 \times \text{Distance}_2 )

Solve for ( \text{Distance}_2 ):

( \text{Distance}_2 = \frac{7 \times 2}{3} = \frac{14}{3} ) meters

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.