A balanced lever has two weights on it, the first with mass #6 kg # and the second with mass #45 kg#. If the first weight is # 9 m# from the fulcrum, how far is the second weight from the fulcrum?
A body which has no tendency to rotate under the combined result of a number of forces acting on it is called to be a balanced state.
The rotational tendency of a force is called Moment of the force.
Also in a balanced lever clockwise moments are equal to clockwise moments.
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Using the principle of moments for a balanced lever:
[ \text{Moment of first weight} = \text{Moment of second weight} ]
[ (6 \text{ kg}) \times (9 \text{ m}) = (45 \text{ kg}) \times (\text{distance of second weight from fulcrum}) ]
[ 6 \times 9 = 45 \times (\text{distance of second weight from fulcrum}) ]
[ \text{Distance of second weight from fulcrum} = \frac{6 \times 9}{45} ]
[ \text{Distance of second weight from fulcrum} = \frac{54}{45} ]
[ \text{Distance of second weight from fulcrum} = 1.2 \text{ meters} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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