A balanced lever has two weights on it, the first with mass #6 kg # and the second with mass #4 kg#. If the first weight is # 5 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Second weight is #7.5# #m# far from fulcrum.

Let the the second weight be #x# #m# far from the fulcrum.
As the lever is balanced, moment (#M=F*d#, where #F# is force applied and #d# is its distance from fulcrum) of the two weights should be equal.
Moment of first weight is #6*5=30# and as it balances second weight of #4# kg, the latter's distance should be
#30/4=7.5# #m#.
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Answer 2

[ \text{Lever equation: } \text{Weight}_1 \times \text{Distance}_1 = \text{Weight}_2 \times \text{Distance}_2 ] [ 6 , \text{kg} \times 5 , \text{m} = 4 , \text{kg} \times \text{Distance}_2 ] [ \text{Distance}_2 = \frac{6 , \text{kg} \times 5 , \text{m}}{4 , \text{kg}} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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