A balanced lever has two weights on it, the first with mass #5 kg # and the second with mass #8 kg#. If the first weight is # 4 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

#x=2.5m#

First of all remember that the principle of moments must apply which is the anticlockwise moment=clockwise moment. Now use the formula #F*d=F*d# but before that convert the masses into weight by multiplying by 10 which is the gravitational force so #5*10=50N# #8*10=80N# no using the formula #50*4=80*x# #x=2.5m#

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Answer 2

Parker Abbott

Using the principle of moments, the product of the mass and distance from the fulcrum must be equal for both weights. Therefore, the distance of the second weight from the fulcrum can be calculated as follows:

Mass1 × Distance1 = Mass2 × Distance2

5 kg × 4 m = 8 kg × Distance2

Distance2 = (5 kg × 4 m) / 8 kg

Distance2 = 20 m / 8 kg

Distance2 = 2.5 m

Therefore, the second weight is 2.5 meters from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.