A balanced lever has two weights on it, the first with mass #5 kg # and the second with mass #60 kg#. If the first weight is # 6 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

#b=1/2=0,5 m#

#F_1:" First weight"# #F_2:" Second weight"# #a:" distance between F_1 and fulcrum"# #b:" distance between F_2 and fulcrum"# #"you can write balance equation by:"# #F_1*a=F_2*b# #5*6=60*b# #cancel(30)=cancel(60)*b# #b=1/2=0,5 m#

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Answer 2

Adam Arnold

To find the distance of the second weight from the fulcrum, use the formula:

[ \text{Weight}_1 \times \text{Distance}_1 = \text{Weight}_2 \times \text{Distance}_2 ]

[ 5 , \text{kg} \times 6 , \text{m} = 60 , \text{kg} \times \text{Distance}_2 ]

[ \text{Distance}_2 = \frac{5 , \text{kg} \times 6 , \text{m}}{60 , \text{kg}} ]

[ \text{Distance}_2 = 0.5 , \text{m} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.