A balanced lever has two weights on it, the first with mass #5 kg # and the second with mass #3 kg#. If the first weight is # 6 m# from the fulcrum, how far is the second weight from the fulcrum?
10 meters
Imagine a see-saw where two people sit on either end.
They're balanced again! So, we've changed two variables: weight and distance. The ability to rotate around a fulcrum, torque, is dependent on force and distance.
If a system is not rotating, clockwise and counter-clockwise rotation are balanced:
In our case:
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[ \text{Distance of second weight from fulcrum} = \frac{\text{Weight of first mass} \times \text{Distance of first mass from fulcrum}}{\text{Weight of second mass}} ]
[ \text{Distance of second weight from fulcrum} = \frac{(5 , \text{kg} \times 6 , \text{m})}{3 , \text{kg}} = 10 , \text{m} ]
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To find the distance of the second weight from the fulcrum:
(First weight mass × First weight distance) = (Second weight mass × Second weight distance)
(5 kg × 6 m) = (3 kg × Second weight distance)
Second weight distance = (5 kg × 6 m) / 3 kg
Second weight distance = 10 m
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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