# A balanced lever has two weights on it, the first with mass #4 kg # and the second with mass #6 kg#. If the first weight is # 8 m# from the fulcrum, how far is the second weight from the fulcrum?

The equation is

Where

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To find the distance of the second weight from the fulcrum, use the principle of moments: ( \text{Moment}_1 = \text{Moment}_2 ).

( \text{Moment}_1 = \text{force}_1 \times \text{distance}_1 = 4 , \text{kg} \times 8 , \text{m} = 32 , \text{Nm} ).

( \text{Moment}_2 = \text{force}_2 \times \text{distance}_2 = 6 , \text{kg} \times \text{distance}_2 ).

Setting the moments equal: ( 32 , \text{Nm} = 6 , \text{kg} \times \text{distance}_2 ).

Solve for distance_2: ( \text{distance}_2 = \frac{32 , \text{Nm}}{6 , \text{kg}} = 5.33 , \text{m} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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