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A balanced lever has two weights on it, the first with mass #3 kg # and the second with mass #4 kg#. If the first weight is # 3 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Sebastian Acosta

2.25m

for Blance, we know,

#M_2/M_1=A/B#

suppose, B= #xm#

so,

#(4kg)/(3kg)=3/x#

#or,x=(3xx3)/4#

#or,x=2.25#

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Answer 2

Adrian Ayala

To find the distance of the second weight from the fulcrum, we can use the principle of moments, which states that the moments (torques) on each side of a balanced lever are equal.

Moment of the first weight = Moment of the second weight (3 kg) * (3 m) = (4 kg) * (x m)

Solving for x: (3 kg) * (3 m) = (4 kg) * (x m) 9 kgm = 4x kgm x = 9/4

So, the second weight is ( \frac{9}{4} ) meters from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.