# A balanced lever has two weights on it, the first with mass #3 kg # and the second with mass #9 kg#. If the first weight is # 6 m# from the fulcrum, how far is the second weight from the fulcrum?

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To find the distance of the second weight from the fulcrum, we can use the principle of moments, which states that the sum of the anticlockwise moments is equal to the sum of the clockwise moments in a balanced lever system.

Let's denote the distance of the second weight from the fulcrum as ( x ) meters.

The moment produced by the first weight is ( 3 \times 6 = 18 ) Nm (since moment = force × distance).

For the system to be balanced, the moment produced by the second weight must also be ( 18 ) Nm.

So, we have ( 9 \times x = 18 ).

Solving for ( x ):

[ 9x = 18 ]

[ x = \frac{18}{9} ]

[ x = 2 ]

Therefore, the second weight is ( 2 ) meters from the fulcrum.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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