A balanced lever has two weights on it, the first with mass #16 kg # and the second with mass #36 kg#. If the first weight is # 2 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

#0.889m#

From the second condition of static equilibrium, the resultant torque must be zero, ie #sum vec tau = 0# where #vec tau = vec r xx vec F#. #therefore r_1F_1-r_2F_2=0# #therefore (2xx16g)-r_2xx36g=0# #therefore r_2=0.889m#.

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Answer 2

Adam Arnold

To find the distance of the second weight from the fulcrum:

16 kg * 2 m = 36 kg * x

x = (16 kg * 2 m) / 36 kg

x = 32 m / 36

x = 0.8889 m

The second weight is approximately 0.8889 meters from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.