Home > Physics > Simple Machines

A balanced lever has two weights on it, the first with mass #15 kg # and the second with mass #9 kg#. If the first weight is # 6 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Isabella Alvarez

10m

The torques balance each other. therefore, #r_1xxF_1=r_2xxF_2# #F=m*g# #m_1*g*r_1=m_2*g*r_2# #15xxgxx6=9xxgxxr_2#

Solving this equation we get #r_2=10m#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Lily Adams

To find the distance of the second weight from the fulcrum, you can use the principle of moments:

[ \text{Moment}_1 = \text{Moment}_2 ]

[ \text{Mass}_1 \times \text{Distance}_1 = \text{Mass}_2 \times \text{Distance}_2 ]

[ 15 , \text{kg} \times 6 , \text{m} = 9 , \text{kg} \times \text{Distance}_2 ]

[ \text{Distance}_2 = \frac{15 , \text{kg} \times 6 , \text{m}}{9 , \text{kg}} ]

[ \text{Distance}_2 = 10 , \text{m} ]

Therefore, the second weight is 10 meters from the fulcrum.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.