A balanced lever has two weights on it, the first with mass #1 kg # and the second with mass #4 kg#. If the first weight is # 25 m# from the fulcrum, how far is the second weight from the fulcrum?

Answer 1

Benjamin Asiedu

#6.25 \ "m"#

For a balanced lever, we have the following relationship:

#m_1d_1=m_2d_2#

#m_1,m_2# are the masses of the two objects

#d_1,d_2# are distances of the two objects from the fulcrum

And so,

#1 \ "kg"*25 \ "m"=4 \ "kg"*d_2#

#d_2=(1color(red)cancelcolor(black)"kg"*25 \ "m")/(4color(red)cancelcolor(black)"kg")#

#=6.25 \ "m"#

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Answer 2

Olivia Askew

The second weight is 6.25 meters from the fulcrum.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.