# A balanced lever has two weights on it, one with mass #5 kg# and one with mass #20 kg#. If the first weight is # 9 m# from the fulcrum, how far is the second weight from the fulcrum?

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To find the distance of the second weight from the fulcrum, you can use the principle of moments. The total clockwise moment equals the total anticlockwise moment. Mathematically, this can be expressed as: (Mass of first weight) × (Distance of first weight from fulcrum) = (Mass of second weight) × (Distance of second weight from fulcrum). Substituting the given values, you get: (5 kg) × (9 m) = (20 kg) × (distance of second weight from fulcrum). Solving for the distance of the second weight from the fulcrum: Distance of second weight from fulcrum = (5 kg × 9 m) / 20 kg = 45/20 = 2.25 m. Therefore, the second weight is 2.25 meters from the fulcrum.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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