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A 5500-kg freight truck accelerates from 4.2 m/s to 7.8 m/s in 15.0 s by the application of a constant force. What change in momentum occurs?

Answer 1

Benjamin Asiedu

Change in momentum is #19800# #kg.m/s#

As initial velocity is #4.2m/s# and final velocity is #7.8m/s#

Initial momentum is #5500xx4.2=23100# #kg.m/s# and

final momentum is #5500xx7.8=42900# #kg.m/s#

#:.# Change in momentum is #42900-23100=19800# #kg.m/s#

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Answer 2

Adam Arnold

To find the change in momentum, we can use the formula:

[ \text{Change in momentum} = \text{Final momentum} - \text{Initial momentum} ]

We can calculate the initial momentum using the formula ( \text{momentum} = \text{mass} \times \text{velocity} ). Then, we find the final momentum using the same formula. Finally, subtract the initial momentum from the final momentum to get the change in momentum.

Given: Mass (( m )) = 5500 kg Initial velocity (( v_i )) = 4.2 m/s Final velocity (( v_f )) = 7.8 m/s

Calculate the initial momentum (( p_i )): [ p_i = m \times v_i ]

Calculate the final momentum (( p_f )): [ p_f = m \times v_f ]

Calculate the change in momentum: [ \text{Change in momentum} = p_f - p_i ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.