A 50.00 mL 1.5 M of #NaOH# titrated with 25.00 ml of #H_3PO_4# (aq). What is the concentration of the is #H_3PO_4# solution?

Question

Ellie Andrews · Accepted Answer

#[H_3PO_4]-=1.50*mol*L^-1#

We monitor the reaction that is stoichiometric.

#H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)#

And it is a fact that phosphoric acid acts as DIACID in aqueous solution. #Na_3PO_4# WILL NOT BE ACCESSED even at high #pH#.

#"Moles of NaOH"=50.00xx10^-3Lxx1.5*mol*L^-1=0.075*mol#.....

And thus, with respect to #H_3PO_4#, there was a #(0.075*mol)/2# molar quantity.......

And #[H_3PO_4]=((0.075*mol)/2)/(25.00*mLxx10^-3*L*mL^-1)#

#=(0.075*mol)/2# of course, we might have been able to nut this result out directly, had we been on the ball in the first instance.

Owen Ambrose · Answer

undefined The balanced chemical equation for the reaction between NaOH and H₃PO₄ is:

3 NaOH + H₃PO₄ → Na₃PO₄ + 3 H₂O

Using the equation, you can determine the number of moles of NaOH reacting with H₃PO₄. Then, using the volume and concentration of H₃PO₄, you can calculate its concentration.

Moles of NaOH = (volume of NaOH) × (concentration of NaOH)
Moles of H₃PO₄ = Moles of NaOH / 3 (from the balanced equation)
Concentration of H₃PO₄ = Moles of H₃PO₄ / volume of H₃PO₄

Xavier Avery · Answer

undefined To find the concentration of the H3PO4 solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and H3PO4.

The balanced chemical equation for the reaction between NaOH and H3PO4 is:

3 NaOH + H3PO4 → Na3PO4 + 3 H2O

From the equation, we can see that the ratio of NaOH to H3PO4 is 3:1.

Given that 50.00 mL of 1.5 M NaOH is titrated with 25.00 mL of the H3PO4 solution, we can set up the following equation using the concept of stoichiometry:

$50.00 \text{ mL} \times 1.5 \text{ M} = 25.00 \text{ mL} \times \text{concentration of } \text{H}_3\text{PO}_4$

Solving for the concentration of H3PO4, we get:

$\text{Concentration of H}_3\text{PO}_4 = \frac{50.00 \times 1.5}{25.00}$

$\text{Concentration of H}_3\text{PO}_4 = 3.0 \text{ M}$

Therefore, the concentration of the H3PO4 solution is 3.0 M.