A 4.0 g sample of iron was heated from 0°C to 20°C. It absorbed 35.2 J of energy as heat. What is the specific heat of this piece of iron?

Answer 1

The specific heat capacity of the iron is #"0.44 J·°C"^"-1""g"^"-1"#.

The equation for the heat that a material absorbs is

#color(blue)(|bar(ul(color(white)(a/a) q = mcΔT color(white)(a/a)|)))" "#

where

#q# is the quantity of heat
#m# is the mass of the substance
#c# is the specific heat capacity of the material
#ΔT# is the temperature change

The formula to determine the specific heat capacity can be rearranged as follows:

#c = q/(mΔT)#
#ΔT = "(20 - 0) °C" = "20 °C"#
#c = "35.2 J"/"4.0 g × 20 °C" = "0.44 J·°C"^"-1""g"^"-1"#
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Answer 2

The specific heat of iron is 0.450 J/(g°C).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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