A 3cm tall object is placed 40cm from a concave mirror with a focal distance of 16cm. The object is moved to 10cm from the same mirror. How would you calculate the distance to the image from the lens, the magnification, and the height of the image?
"Lens" should, in my opinion, be "mirror."
To determine the image distance, we can apply the mirror equation:
Additionally, making use of the fact that
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To calculate the distance to the image from the lens (image distance), the magnification, and the height of the image, you can use the mirror equation and the magnification formula.

Distance to the image from the lens (image distance): [ \frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i} ] Where:
 ( f ) = focal length of the concave mirror (given as 16 cm since it's concave)
 ( d_o ) = object distance (initially 40 cm, then moved to 10 cm)
 ( d_i ) = image distance (unknown)

Magnification (height of the image): [ M = \frac{d_i}{d_o} ] Where:
 ( M ) = magnification
 ( d_i ) = image distance (from the first calculation)
 ( d_o ) = object distance (initially 40 cm, then moved to 10 cm)

Height of the image: [ h_i = M \times h_o ] Where:
 ( h_i ) = height of the image
 ( M ) = magnification (from the second calculation)
 ( h_o ) = height of the object (given as 3 cm)
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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