A #3# kilogram object is acted upon by an impulse having a magnitude of #15# #N*s#. What is the magnitude of the object's change in momentum due to this impulse?

Answer 1

#15 kg.m//s#

Newton's 2nd law of motion may also be stated in terms of momentum as follows : The resultant force acting on an object is directly proportional to the rate of change in momentum brought about. ie. #sum vecF= (d vecp)/(dt)#, where #vecp = m vecv#.

Rearranging yields : #sum vecF dt = m d vecv#.

Thus impulse (#sum vecFdt#) equals change in momentum (#m d vec v = d vecp#)

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Answer 2

Xavier Adame

The magnitude of the object's change in momentum due to the impulse is 15 kg*m/s.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.